The members of an association decided to contribute equally to create a fund of Tk. 45,000. Five members refused to contribute, so each of the other members had to contribute additional tk. 15 for that fund. How many members were there in the association?
A. 120
B. 125
C. 130
D. 135
Explanation: Let the number of members be x, and the original amount contributed by each member be y. Therefore, \(45000/x = y\). Hence, \((x-5) (y+15) = 45000\). \((x-5) [\frac{45000}{x} + 15] = 45000\). \(45000+15x-225000/x-75 = 45000\). \(15x^2-225000-75x = 0\). \(x^{2}-5x-15000=0 \implies x=125\).
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