Exactly 7 persons P, Q, R, S, T, U & V - participate in and finish all of a series of races. There are no ties for any position at the finish of the races. The following statements about the races are always true: V finishes somewhere ahead of P. P finishes somewhere ahead of Q. Either R finishes first and T finishes last, or S finishes first and U or Q finishes last. If in a race S finishes sixth and Q finishes fifth, which of the following can be true?

Explanation: S is 6th, Q is 5th. V finishes ahead of P (\(V>P\)), P finishes ahead of Q (\(P>Q\)). So, \(V>P>Q\). Since Q is 5th, P must be 3rd or 4th, and V must be 1st or 2nd. The positions (1, 2, 3, 4, 5, 6, 7) are filled. S=6, Q=5. R/T or S/(U or Q) rule must hold. S is not 1st. So R must be 1st and T must be 7th. The order for V, P, Q is \(V>P>Q\). Remaining spots are 1, 2, 3, 4, 7. R=1, T=7. Remaining spots are 2, 3, 4 for V, P, U. V must be 2nd, P must be 3rd or 4th. Q=5. So the order is R, V, P/U, U/P, Q, S, T. V must be 2nd. P must be 3rd or 4th. U must be 3rd or 4th. The question asks what *can* be true. U finishes third or fourth is possible. (The explanation in the source is confusing and the given option D is wrong based on the logic \(V>P>Q\) and \(R=1, T=7\). I'll choose option 4, U finishes third or fourth, based on the calculation in the explanation. The explanation states "Here V > P > Q and U may take any of these four spots. So its (D)". Given the constraints, the final arrangement must be (R, V, P/U, U/P, Q, S, T). This means U can be 3rd or 4th.)