$\theta = \sin^{-1}\left(\frac{3}{5}\right)$ হলে, $\frac{1-\tan^2\theta}{1+\tan^2\theta} = ?$ (If $\theta = \sin^{-1}\left(\frac{3}{5}\right)$, then $\frac{1-\tan^2\theta}{1+\tan^2\theta} = ?$)

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সঠিক উত্তর: $\frac{7}{25}$। ব্যাখ্যা:

\(\theta = \sin^{-1}\left(\frac{3}{5}\right)\) হলে, \(\frac{1-\tan^2\theta}{1+\tan^2\theta} = ?\) (If \(\theta = \sin^{-1}\left(\frac{3}{5}\right)\), then \(\frac{1-\tan^2\theta}{1+\tan^2\theta} = ?\))