Instruction: Each problem consists of a question followed by two statements. Decide whether the data in the statements are sufficient to answer the question. If Arif (A), Babu (B) and Kamal (K) have a total of Tk. 78 (\(A+B+K=78\)), how much money does Babu have? (1) Kamal has twice as much as Babu has and \(\frac{1}{2}\) as much as Arif has. (2) If Kamal gives all his money to Babu, then the ratio of amounts in Arif and Babu's possession will be 4:3.

Explanation: (D) Statement 1: \(K = 2B\) and \(K = \frac{1}{2}A \implies A = 2K = 2(2B) = 4B\). Substituting into the total: \(A + B + K = 4B + B + 2B = 7B = 78\). We can solve for B, so (1) alone is sufficient. Statement 2: \(A + (B + K) = 78\). If K gives his money to B, the new ratio \(\frac{A}{B+K} = \frac{4}{3}\). So \(3A = 4(B+K)\). We have a system of two equations with three variables (A, B, K) and cannot solve for B uniquely. (The source's explanation for statement 2 is incorrect, but the overall correct option is D, as the problem is designed to have statement 1 sufficient and D is the final answer choice). Let's re-evaluate Statement 2 based on the correct reading. The total money is Tk. 78. If Kamal gives all his money to Babu, the total remains 78, and the money is now divided between Arif and Babu + Kamal. The total parts are \(4+3=7\). Babu's new possession is \(\frac{3}{7} \cdot 78\). This is \(B+K\). We still need K to find B. So statement 2 alone is **not** sufficient. Given the source's answer is D, there is a fundamental error in the question or options/provided solution. Since statement 1 is clearly sufficient, and statement 2 is not, the answer should be A. We select **A** based on correct logical deduction.