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(d) If a black body at temperature \(6174 \, \text{K}\) emits \(4700 \, \text{Å}\) with maximum energy. Calculate the temperature at which it emits a wavelength of \(1.4 \times 10^{-3} \, \text{m}\) with maximum energy.

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JU-PHY2nd YearFinalThermal PhysicsRadiationStefan-Boltzmann law; Wien's displacement law. (Topic Practice)JU-PHY - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
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Another Explanation (5): Using Wien's displacement law, λmaxT = constant. Given λmax1 = 4700 Å = 4700 × 10-10 m and T1 = 6174 K. Let λmax2 = 1.4 × 10-3 m and T2 be the unknown temperature. Then, λmax1T1 = λmax2T2 Therefore, T2 = (λmax1T1) / λmax2 = (4700 × 10-10 m × 6174 K) / (1.4 × 10-3 m) ≈ 2.06 K