মেনু
QB Archive Quiz Creator Graph Poll Mode View Ques Quiz Leaderboard About
থিম নির্বাচন

আপনার পছন্দের থিম বেছে নিন।

Download Address Academy - Best Offline Education App

(h) Calculate the energy radiated per minute from the filament of an incandescent Lamp at 1500 K if the surface area is \(4.5 \times 10^{-5} \, \text{m}^2\) and its relative emittance is \(0.65 \, (\sigma = 5.672 \times 10^{-8} \, \text{W/m}^2\text{K}^4)\).

A.
B.
C.
D.
Poster Download
JU-PHY2nd YearFinalThermal PhysicsRadiationStefan-Boltzmann law; Wien's displacement law. (Topic Practice)JU-PHY - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
Join Telegram
Another Explanation (5):

Using Stefan-Boltzmann Law: Power (P) = εσAT4

P = (0.65) × (5.672 × 10-8 W/m2K4) × (4.5 × 10-5 m2) × (1500 K)4

P ≈ 0.149 W

Energy per minute = P × 60 s = 0.149 W × 60 s ≈ 8.94 J

Therefore, the energy radiated per minute is approximately 8.94 J.