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(f) Calculate the surface temperature of sun and moon given that \( \lambda_m = 4753 \text{\AA} \) and \( 14 \mu \text{m} \) respectively, \( \lambda_m \) being wavelength of maximum intensity of emission.

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JU-PHY2nd YearFinalThermal PhysicsRadiationStefan-Boltzmann law; Wien's displacement law. (Topic Practice)JU-PHY - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
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Another Explanation (5): Using Wien's displacement law, \( \lambda_m T = b \), where \( b = 2.898 \times 10^{-3} \, m \cdot K \) is Wien's displacement constant. For the Sun: \( T_{sun} = \frac{b}{\lambda_m} = \frac{2.898 \times 10^{-3} \, m \cdot K}{4753 \times 10^{-10} \, m} \approx 6100 \, K \) For the Moon: \( T_{moon} = \frac{b}{\lambda_m} = \frac{2.898 \times 10^{-3} \, m \cdot K}{14 \times 10^{-6} \, m} \approx 207 \, K \) Therefore: * Sun's surface temperature: approximately 6100 K * Moon's surface temperature: approximately 207 K