Two similar triangles have areas of $18 cm^{2}$ and $32 cm^{2}$. If the base of the smaller triangle is 6 cm, find the base of the larger triangle.

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সঠিক উত্তর: । ব্যাখ্যা: $\frac{18}{32} = \frac{6^{2}}{x^{2}} \Rightarrow \frac{9}{16} = \frac{36}{x^{2}} \Rightarrow 9x^{2} = 16 \times 36 \Rightarrow x^{2} = 16 \times 4 \Rightarrow x^{2} = 64 \Rightarrow x=8$

Two similar triangles have areas of \(18 cm^{2}\) and \(32 cm^{2}\). If the base of the smaller triangle is 6 cm, find the base of the larger triangle.