cosA=12/13 হলে, tanA এর মান কত?

Explanation:

Another Explanation (5): ```html cosA = \(\frac{12}{13}\) দেওয়া আছে।
আমরা জানি, \(sin^2A + cos^2A = 1\)
সুতরাং, \(sin^2A = 1 - cos^2A\)
\(sin^2A = 1 - (\frac{12}{13})^2\)
\(sin^2A = 1 - \frac{144}{169}\)
\(sin^2A = \frac{169 - 144}{169}\)
\(sin^2A = \frac{25}{169}\)
অতএব, \(sinA = \pm\frac{5}{13}\) 🎉
এখন, \(tanA = \frac{sinA}{cosA}\)
\(tanA = \frac{\pm\frac{5}{13}}{\frac{12}{13}}\)
\(tanA = \pm\frac{5}{13} \times \frac{13}{12}\)
সুতরাং, \(tanA = \pm\frac{5}{12}\) 🥳
```