What is the depth of water below the surface of a dam where the pressure is 1.00 atm?

প্রদত্ত, 🤔

Pressure, \( P = 1.00 \text{ atm} = 1.013 \times 10^5 \text{ Pa} \) 😮

Density of water, \( \rho = 1000 \text{ kg/m}^3 \)💧

Acceleration due to gravity, \( g = 9.81 \text{ m/s}^2 \)🌍

নির্ণয় করতে হবে, ❓

Depth, \( h = ? \)

ব্যাখ্যা: 🤓

Pressure at a depth \(h\) below the surface of a fluid is given by:

\( P = \rho g h \) 🧮

Where,

\(P\) = Pressure

\(\rho\) = Density of the fluid

\(g\) = Acceleration due to gravity

\(h\) = Depth

Rearranging the formula to solve for \(h\):

\( h = \frac{P}{\rho g} \) 📐

সমাধান: ➗

Substituting the given values:

\( h = \frac{1.013 \times 10^5 \text{ Pa}}{1000 \text{ kg/m}^3 \times 9.81 \text{ m/s}^2} \) 👍

\( h = \frac{1.013 \times 10^5}{9810} \text{ m} \) 💫

\( h = 10.326 \text{ m} \) 💯

Rounded to two decimal places: \( h \approx 10.33 \text{ m} \)✅

Therefore, the depth of water below the surface of the dam where the pressure is 1.00 atm is approximately 10.33 meters.