(g) A black sphere of diameter 4 cm is heated to 400 K when the surrounding temperature is 300 K. What is the rate at which energy is radiated? Given \( \sigma = 6 \times 10^{-8} \, \text{Wm}^{-2} \, \text{K}^{-4} \).
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JU-PHY2nd YearFinalThermal PhysicsRadiationStefan-Boltzmann law; Wien's displacement law. (Topic Practice)JU-PHY - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
Another Explanation (5):
The surface area of the sphere is A = 4πr² = 4π(0.02 m)² ≈ 0.005 m².
Using Stefan-Boltzmann's Law, the rate of energy radiated (P) is given by:
P = εσA(T⁴ - T0⁴)
where:
- σ = 6 × 10⁻⁸ Wm⁻²K⁻⁴
- ε = 1 (for a black body)
- A = 0.005 m²
- T = 400 K
- T₀ = 300 K
Substituting the values:
P = (1)(6 × 10⁻⁸ Wm⁻²K⁻⁴)(0.005 m²)((400 K)⁴ - (300 K)⁴) ≈ 1.71 W
Related Questions (Any University/Year)
- (c) What is the wavelength of maximum intensity radiation radiated from a source at temperature \(3000^\circ \text{C}\)? (Wien's constant \(b = 0.288 \, \text{cm} \cdot \text{K}\)).
- (d) Calculate the maximum amount of heat which may be lost per second by radiation from a sphere of 5 cm in diameter at a temperature of 600 K when placed in an enclosure at a temperature of 300 K. Given that, \(\sigma = 5.7 \times 10^{-12} \, \text{watts/cm}^{-2}/(^\circ \text{C})^{-1}\).
- (j) State Wien’s displacement law.
- (d) Calculate the maximum amount of heat which may be lost per second by radiation from a sphere of 5 cm in diameter at a temperature of 600 K when is placed in an encloser at a temperature of 300 K. Given that \(\sigma = 5.7 \times 10^{-12} \, \text{watts/cm}^{-2} / (\circ C)^{-4}\).
- (b)State and explain Wein's displacement law.
- (k)What is Stefan-Boltzmann law? State Wein's displacement law.
- g) What is Stefan-Boltzmann law?
- (4) The spectral energy curve of sunlight has a maximum at a wavelength of \(4.84 \times 10^{-7} \, \text{m}\). Assuming the Sun to be a black body,
- (c) A black body at temperature 4980 K emits radiation of wavelength 4000 Å with maximum energy. Calculate the temperature at which it will emit a wavelength of \(1.45 \times 10^{-5} \, \text{cm}\) with maximum energy.
- (h) Calculate the energy radiated per minute from the filament of an incandescent Lamp at 1500 K if the surface area is \(4.5 \times 10^{-5} \, \text{m}^2\) and its relative emittance is \(0.65 \, (\sigma = 5.672 \times 10^{-8} \, \text{W/m}^2\text{K}^4)\).
- (a) What is the temperature of its emitting surface?
- b) Derive Wien's law of energy distribution.
- (f) Calculate the surface temperature of sun and moon given that \( \lambda_m = 4753 \text{\AA} \) and \( 14 \mu \text{m} \) respectively, \( \lambda_m \) being wavelength of maximum intensity of emission.
- (b) State and explain Stefan-Boltzmann's law.
- (d) An aluminum foil of relative emittance 0.1 is placed in between two concentric spheres at temperatures 300 K and 200 K respectively. Calculate the temperature of the foil after the steady state is reached. Assume that the spheres are perfect blackbody radiators. Also calculate the rate of energy transfer between one of the spheres and the foil. [\(\sigma = 5.672 \times 10^{-8} \, \text{M.K.S. units}\)]
- (c)Calculate the surface temperature of sun and moon given that \( \lambda_m = 4753 \, \text{Å} \) and 14 \(\mu \text{m}\) respectively, \( \lambda_m \) being wavelength at the maximum intensity of emission.
- (5) Two large closely spaced concentric spheres (both are black body radiators) are maintained at temperatures of 200 K and 300 K respectively. The space in between the two spheres is evacuated. Calculate the net rate of energy transfer between the two spheres. [Given: \(\sigma = 5.672 \times 10^{-8} \, \text{W/m}^2\text{K}^4\)]
- f) If a blackbody at temperature 6174 K emits 4700 Å with maximum energy, calculate the temperature at which it will emit a wavelength of \(1.4 \times 10^{-3}\) m with maximum energy.
- (b) What is the energy density of the Sun's radiation?
- (xiii) State Stefan-Boltzmann law.