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(c)Calculate the surface temperature of sun and moon given that \( \lambda_m = 4753 \, \text{Å} \) and 14 \(\mu \text{m}\) respectively, \( \lambda_m \) being wavelength at the maximum intensity of emission.

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JU-PHY2nd YearFinalThermal PhysicsRadiationStefan-Boltzmann law; Wien's displacement law. (Topic Practice)JU-PHY - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
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Another Explanation (5): Using Wien's Displacement Law, \( \lambda_m T = b \), where \( b = 2.898 \times 10^{-3} \, \text{mK} \). For the Sun: \( T_{sun} = \frac{b}{\lambda_m} = \frac{2.898 \times 10^{-3} \, \text{mK}}{4753 \times 10^{-10} \, \text{m}} \approx 6100 \, \text{K} \) For the Moon: \( T_{moon} = \frac{b}{\lambda_m} = \frac{2.898 \times 10^{-3} \, \text{mK}}{14 \times 10^{-6} \, \text{m}} \approx 207 \, \text{K} \)