If \(x \le 4\times12\) and \(-2 < y \le 13\) which of the following numbers represent the maximum value of \((y-x)\)?

Explanation: The question text has a typo: \(x \le 4\times12\) is transcribed as \(-4 < x \le 12\) in the attempt, but the actual question seems to be \(7. H - 4 \times 12\) and the working takes a range for x as \(-4 < x \le 12\). Assuming the working's interpretation: $x \le 12$ and $x > -4$. $y \le 13$ and $y > -2$. Maximum value of \((y-x)\) is achieved when $y$ is maximum and $x$ is minimum. Max $y = 13$. Min $x$ is slightly greater than $-4$. The question is likely intended to be \(-4 \le x \le 12\). Assuming \(x \ge -4\) (since $x$ is used as an integer in the working, though not specified): Minimum value of \(x\) is \(-4\). Maximum value of \((y-x) = \text{Max } y - \text{Min } x = 13 - (-4) = 17\).