SinA=1/5 হলে tanA এর মান হচ্ছে-

Explanation:

Another Explanation (5): ```html Sin A = 1/5 হলে, tan A এর মান নির্ণয়: আমরা জানি, \(sin^2 A + cos^2 A = 1\) সুতরাং, \(cos^2 A = 1 - sin^2 A\) \(cos^2 A = 1 - (1/5)^2\) \(cos^2 A = 1 - 1/25\) \(cos^2 A = 24/25\) অতএব, \(cos A = \pm \sqrt{24/25}\) \(cos A = \pm \frac{\sqrt{24}}{5}\) \(cos A = \pm \frac{2\sqrt{6}}{5}\) এখন, \(tan A = \frac{sin A}{cos A}\) \(tan A = \frac{1/5}{\pm \frac{2\sqrt{6}}{5}}\) \(tan A = \pm \frac{1}{2\sqrt{6}}\) সুতরাং, \(tan A = \pm \frac{1}{2\sqrt{6}}\) 🥳 ```