যদি  cosA =12/13   হয়,  তবে tanA এর মান কত ?  

Explanation:

Another Explanation (5): দেওয়া আছে, \( \cos A = \frac{12}{13} \) আমরা জানি, \( \sin^2 A + \cos^2 A = 1 \) সুতরাং, \( \sin^2 A = 1 - \cos^2 A \) \( \sin^2 A = 1 - \left(\frac{12}{13}\right)^2 \) \( \sin^2 A = 1 - \frac{144}{169} \) \( \sin^2 A = \frac{169 - 144}{169} \) \( \sin^2 A = \frac{25}{169} \) অতএব, \( \sin A = \pm \sqrt{\frac{25}{169}} = \pm \frac{5}{13} \) এখন, \( \tan A = \frac{\sin A}{\cos A} \) সুতরাং, \( \tan A = \frac{\pm \frac{5}{13}}{\frac{12}{13}} = \pm \frac{5}{13} \cdot \frac{13}{12} = \pm \frac{5}{12} \) অতএব, \( \tan A = \pm \frac{5}{12} \) 🥳🎉