If f(x)=2x⁴-4 andg=sqrt((x-2)/(sqrt2)) then what is the value of fog(5)?

Explanation:

Another Explanation (5): f(x) = 2x⁴ - 4 এবং g(x) = \(\sqrt{\frac{x-2}{\sqrt{2}}}\) হলে, fog(5) এর মান নির্ণয়: প্রথমে g(5) এর মান বের করি: g(5) = \(\sqrt{\frac{5-2}{\sqrt{2}}} = \sqrt{\frac{3}{\sqrt{2}}}\) এখন, fog(5) = f(g(5)) = \(f(\sqrt{\frac{3}{\sqrt{2}}})\) f(x) = 2x⁴ - 4, তাই \(f(\sqrt{\frac{3}{\sqrt{2}}}) = 2(\sqrt{\frac{3}{\sqrt{2}}})^4 - 4\) = \(2(\frac{3}{\sqrt{2}})^2 - 4\) = \(2(\frac{9}{2}) - 4\) = 9 - 4 = 5 অতএব, fog(5) = 5 🥳