(2tanθ)/(1+tan^2θ)=?

Explanation:

Another Explanation (5): দেওয়া আছে, \( \frac{2\tan\theta}{1+\tan^2\theta} \) 🤔 আমরা জানি, \( \tan\theta = \frac{\sin\theta}{\cos\theta} \) 🤓 এবং \( \sec^2\theta = 1 + \tan^2\theta \) 😎 তাহলে, \( \frac{2\tan\theta}{1+\tan^2\theta} = \frac{2\frac{\sin\theta}{\cos\theta}}{\sec^2\theta} \) 🥳 \( = \frac{2\frac{\sin\theta}{\cos\theta}}{\frac{1}{\cos^2\theta}} \) 🤩 \( = 2\frac{\sin\theta}{\cos\theta} \cdot \cos^2\theta \) 😲 \( = 2\sin\theta\cos\theta \) 🥰 সুতরাং, \( \frac{2\tan\theta}{1+\tan^2\theta} = 2\sin\theta\cos\theta \) 🎉