sinθ=12/13 হলে, tanθ এর মান কত ?

Explanation:

Another Explanation (5): দেওয়া আছে, sinθ = 12/13 আমরা জানি, \(sin^2θ + cos^2θ = 1\) সুতরাং, \(cos^2θ = 1 - sin^2θ\) = \(1 - (12/13)^2\) = \(1 - 144/169\) = \((169 - 144) / 169\) = \(25/169\) অতএব, \(cosθ = ±\sqrt{25/169} = ±5/13\) এখন, \(tanθ = sinθ / cosθ\) যদি \(cosθ = 5/13\) হয়, তবে \(tanθ = (12/13) / (5/13) = 12/5\) আবার, যদি \(cosθ = -5/13\) হয়, তবে \(tanθ = (12/13) / (-5/13) = -12/5\) সুতরাং, \(tanθ = ±12/5\) ✅