If  vecF=4hati+3hatj+hatk is the force and  vecS=hati+2hatj+5hatk is the displacement, then what is the amount of work?

Explanation:

Another Explanation (5): ```html

Work done by a force

Given, Force \( \vec{F} = 4\hat{i} + 3\hat{j} + \hat{k} \) and displacement \( \vec{S} = \hat{i} + 2\hat{j} + 5\hat{k} \). Work done, \( W = \vec{F} \cdot \vec{S} \) \( W = (4\hat{i} + 3\hat{j} + \hat{k}) \cdot (\hat{i} + 2\hat{j} + 5\hat{k}) \) \( W = (4 \times 1) + (3 \times 2) + (1 \times 5) \) \( W = 4 + 6 + 5 \) \( W = 15 \) Therefore, the amount of work done is 15 units. 🎉 ```