A=[(1,i),(-i,1)], B=[(i,-1),(-1,-i)] এবং i=sqrt(-1) হলে AB এর মান হবে-

Explanation:

Another Explanation (5): bài giải: \(A = \begin{bmatrix} 1 & i \\ -i & 1 \end{bmatrix}\), \(B = \begin{bmatrix} i & -1 \\ -1 & -i \end{bmatrix}\) \(AB = \begin{bmatrix} 1 & i \\ -i & 1 \end{bmatrix} \begin{bmatrix} i & -1 \\ -1 & -i \end{bmatrix}\) \(AB = \begin{bmatrix} (1)(i) + (i)(-1) & (1)(-1) + (i)(-i) \\ (-i)(i) + (1)(-1) & (-i)(-1) + (1)(-i) \end{bmatrix}\) \(AB = \begin{bmatrix} i - i & -1 - i^2 \\ -i^2 - 1 & i - i \end{bmatrix}\) যেহেতু \(i^2 = -1\), সুতরাং \(AB = \begin{bmatrix} 0 & -1 - (-1) \\ -(-1) - 1 & 0 \end{bmatrix}\) \(AB = \begin{bmatrix} 0 & -1 + 1 \\ 1 - 1 & 0 \end{bmatrix}\) \(AB = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}\) সুতরাং, \(AB = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}\) 🥳🎉