cos200 cos400 cos600 cos800= কত?
CUUnit-ASet-1উচ্চতর গণিত প্রথম পত্রসংযুক্ত কোণের ত্রিকোণমিতিক অনুপাতসংযুক্ত কোণের অনুপাত (Topic Practice)CU - ⚡ অনলাইন প্রশ্নব্যাংক দেখুন 💥
সঠিক উত্তরঃ
D.
1/16
Explanation:


Another Explanation (5):
cos20° cos40° cos60° cos80° -এর মান নির্ণয়:
আমরা জানি, cos60° = 1/2
সুতরাং, cos20° cos40° cos60° cos80° = cos20° cos40° (1/2) cos80°
= (1/2) cos20° cos40° cos80°
এখন,
cos20° cos40° cos80° = (cos20° cos40°) cos80°
আমরা জানি, 2cosA cosB = cos(A+B) + cos(A-B)
সুতরাং, cos20° cos40° = (1/2) [cos(20°+40°) + cos(20°-40°)]
= (1/2) [cos60° + cos(-20°)]
= (1/2) [cos60° + cos20°] ∵ [cos(-θ) = cosθ]
= (1/2) [1/2 + cos20°]
= 1/4 + (1/2) cos20°
অতএব, cos20° cos40° cos80°
= (1/2) [1/2 + cos20°] cos80°
= (1/4) cos80° + (1/2) cos20° cos80°
= (1/4) cos80° + (1/2) * (1/2) [cos(20°+80°) + cos(20°-80°)]
= (1/4) cos80° + (1/4) [cos100° + cos(-60°)]
= (1/4) cos80° + (1/4) [cos100° + cos60°]
= (1/4) cos80° + (1/4) cos100° + (1/4) * (1/2)
= (1/4) cos80° + (1/4) cos(180°-80°) + 1/8
= (1/4) cos80° + (1/4) (-cos80°) + 1/8 ∵ [cos(180°-θ) = -cosθ]
= (1/4) cos80° - (1/4) cos80° + 1/8
= 1/8
সুতরাং, cos20° cos40° cos60° cos80° = (1/2) cos20° cos40° cos80°
= (1/2) * (1/8)
= 1/16
সুতরাং, cos20° cos40° cos60° cos80° = 1/16 🎉