sqrt((1-sinA)/(1+sinA)=? 

Explanation:

Another Explanation (5): সমাধান: \[ \sqrt{\frac{1-\sin A}{1+\sin A}} \] হর এবং লবকে \( (1-\sin A) \) দ্বারা গুণ করে পাই, \[ = \sqrt{\frac{(1-\sin A)(1-\sin A)}{(1+\sin A)(1-\sin A)}} \] \[ = \sqrt{\frac{(1-\sin A)^2}{1-\sin^2 A}} \] আমরা জানি, \( \sin^2 A + \cos^2 A = 1 \), সুতরাং \( 1-\sin^2 A = \cos^2 A \) \[ = \sqrt{\frac{(1-\sin A)^2}{\cos^2 A}} \] \[ = \frac{1-\sin A}{\cos A} \] \[ = \frac{1}{\cos A} - \frac{\sin A}{\cos A} \] আমরা জানি, \( \frac{1}{\cos A} = \sec A \) এবং \( \frac{\sin A}{\cos A} = \tan A \) \[ = \sec A - \tan A \] সুতরাং, \( \sqrt{\frac{1-\sin A}{1+\sin A}} = \sec A - \tan A \) 🥳