Sin A = 12/13 হলে tan A এর মান হয় -

Explanation:

Another Explanation (5): ```html Sin A = \(\frac{12}{13}\) হলে, tan A এর মান নির্ণয়: আমরা জানি, \(sin^2 A + cos^2 A = 1\) সুতরাং, \(cos^2 A = 1 - sin^2 A\) \(cos^2 A = 1 - (\frac{12}{13})^2\) \(cos^2 A = 1 - \frac{144}{169}\) \(cos^2 A = \frac{169 - 144}{169}\) \(cos^2 A = \frac{25}{169}\) অতএব, \(cos A = \pm \frac{5}{13}\) 😃 এখন, \(tan A = \frac{sin A}{cos A}\) 🤓 যখন \(cos A = \frac{5}{13}\), তখন \(tan A = \frac{\frac{12}{13}}{\frac{5}{13}} = \frac{12}{5}\) আবার, যখন \(cos A = -\frac{5}{13}\), তখন \(tan A = \frac{\frac{12}{13}}{-\frac{5}{13}} = -\frac{12}{5}\) সুতরাং, \(tan A = \pm \frac{12}{5}\) 🎉 ```