The sequence $a_1, a_2, a_3, \dots, a_n$ is defined by $a_n = 9 + a_{n-1}$ for each integer $n \ge 2$. If $a_1 = 11$, what is the value of $a_{34}$?

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সঠিক উত্তর: । ব্যাখ্যা: The sequence is an arithmetic progression with a common difference of $d=9$. The formula for the $n$-th term is $a_n = a_1 + (n-1)d$. We need to find $a_{34}$. $n=34$, $a_1=11$, $d=9$. $a_{34} = a_1 + (34-1)d = 11 + (33) \times 9$. $33 \times 9 = 297$. $a_{34} = 11 + 297 = 308$.

The sequence \(a_1, a_2, a_3, \dots, a_n\) is defined by \(a_n = 9 + a_{n-1}\) for each integer \(n \ge 2\). If \(a_1 = 11\), what is the value of \(a_{34}\)?

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