³C₃ + ³C₂ + ³C₁ এর মান কোনটি?

Explanation:

Another Explanation (5): ³C₃ + ³C₂ + ³C₁ এর মান নির্ণয়: আমরা জানি, ⁿC_r = \(\frac{n!}{r!(n-r)!}\) এখানে, ³C₃ = \(\frac{3!}{3!(3-3)!}\) = \(\frac{3!}{3!0!}\) = \(\frac{6}{6 \cdot 1}\) = 1 😮‍💨 ³C₂ = \(\frac{3!}{2!(3-2)!}\) = \(\frac{3!}{2!1!}\) = \(\frac{6}{2 \cdot 1}\) = 3 🥳 ³C₁ = \(\frac{3!}{1!(3-1)!}\) = \(\frac{3!}{1!2!}\) = \(\frac{6}{1 \cdot 2}\) = 3 😎 সুতরাং, ³C₃ + ³C₂ + ³C₁ = 1 + 3 + 3 = 7 🎉