If, sinA=12/13 " " then, Cot A? 

Explanation:

Another Explanation (5): দেওয়া আছে, \( \sin A = \frac{12}{13} \). আমরা জানি, \( \sin^2 A + \cos^2 A = 1 \). সুতরাং, \( \cos^2 A = 1 - \sin^2 A = 1 - \left(\frac{12}{13}\right)^2 = 1 - \frac{144}{169} = \frac{169 - 144}{169} = \frac{25}{169} \). তাহলে, \( \cos A = \pm \sqrt{\frac{25}{169}} = \pm \frac{5}{13} \). এখন, \( \cot A = \frac{\cos A}{\sin A} \). যদি \( \cos A = \frac{5}{13} \) হয়, তবে \( \cot A = \frac{\frac{5}{13}}{\frac{12}{13}} = \frac{5}{13} \times \frac{13}{12} = \frac{5}{12} \). আবার, যদি \( \cos A = -\frac{5}{13} \) হয়, তবে \( \cot A = \frac{-\frac{5}{13}}{\frac{12}{13}} = -\frac{5}{13} \times \frac{13}{12} = -\frac{5}{12} \). অতএব, \( \cot A = \pm \frac{5}{12} \). ✅🎉