If Costheta=12/13, tantheta=? 

Explanation:

Another Explanation (5): দেওয়া আছে, \( \cos\theta = \frac{12}{13} \) আমরা জানি, \( \sin^2\theta + \cos^2\theta = 1 \) সুতরাং, \( \sin^2\theta = 1 - \cos^2\theta \) \( \sin^2\theta = 1 - \left(\frac{12}{13}\right)^2 \) \( \sin^2\theta = 1 - \frac{144}{169} \) \( \sin^2\theta = \frac{169 - 144}{169} \) \( \sin^2\theta = \frac{25}{169} \) অতএব, \( \sin\theta = \pm\sqrt{\frac{25}{169}} = \pm\frac{5}{13} \) এখন, \( \tan\theta = \frac{\sin\theta}{\cos\theta} \) সুতরাং, \( \tan\theta = \frac{\pm\frac{5}{13}}{\frac{12}{13}} = \pm\frac{5}{13} \times \frac{13}{12} = \pm\frac{5}{12} \) অতএব, \( \tan\theta = \pm\frac{5}{12} \) 🥳🎉